(x^2-8x+20)=1/(x^2-2x+6)

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Solution for (x^2-8x+20)=1/(x^2-2x+6) equation: 



(x^2-8x+20)=1/(x^2-2x+6)

We move all terms to the left:

(x^2-8x+20)-(1/(x^2-2x+6))=0



Domain of the equation: (x^2-2x+6))!=0

x∈R



We get rid of parentheses

x^2-8x-(1/(x^2-2x+6))+20=0

We multiply all the terms by the denominator


x^2*(x^2-2x+6))-8x*(x^2-2x+6))-(1+20*(x^2-2x+6))=0

We add all the numbers together, and all the variables

x^2*(x^2-2x+6))-8x*(x^2-4x+6))-(1+20*(x^2=0

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